How do you differentiate $y = sin (x^{2} + 2)$ $y = sin (x^2+2)$ using the chain rule?

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Answer 1 · 2015-12-25T15:24:56

$y'=2x cos(x^2+2)$

To differentiate this, we have to use $D_x Sinu= cosx D_x u$
So $y= sin(x^2+ 2)$
$y'= cos(x^2+2)(2x)$
$y'=2x cos(x^2+2)$

How do you differentiate y = sin (x^2+2)y=sin(x2+2) y = sin (x^2+2) using the chain rule?