How do you solve $x^2=13x-42$ ?

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Answer 1 · 2015-12-27T15:25:46

The roots of $x$ are $7$ and $6$

This equation may be written as

$x^2-13x+42=0$

or

$x^2-7x-6x+42 =0$

or

$x(x-7)-6(x-7)=0$

or

$(x-7)(x-6)=0$

So $x-7=0$ or $x-6=0$

therefore $x=7$ or $6$
[answer]

How do you solve x^2=13x-42x^2=13x-42?