What is the solution to the system of equations $x = y - 1$ $x = y - 1$ and $2 x + y = - 2$ $2x + y = -2$ ?

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What is the solution to the system of equations $x = y - 1$ $x = y - 1$ and $2 x + y = - 2$ $2x + y = -2$ ?

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Answer 1 · 2015-12-28T08:10:44

$x = - 1$ $x=-1$ and $y = 0$ $y=0$

Explanation:

$\times x = y - 1$ $color(white)(xx)x=y-1$ , $2 x + y = - 2$ $2x+y=-2$

$\times 2 x + y = - 2 \Leftrightarrow x = \frac{- y - 2}{2}$ $color(white)xx2x+y=-2<=>x=(-y-2)/2$

$\Rightarrow y - 1 = \frac{- y - 2}{2}$ $=>y-1=(-y-2)/2$
$\Rightarrow 2 \times (y - 1) = 2 \times \frac{- y - 2}{2}$ $=>color(red)(2xx)(y-1)=color(red)(2xx)(-y-2)/2$
$\Rightarrow 2 y - 2 + 2 = - y - 2 + 2$ $=>2y-2color(red)(+2)=-y-2color(red)(+2)$
$\Rightarrow y = 0$ $=>y=0$

$\times x = y - 1$ $color(white)(xx)x=y-1$
$\times x = 0 - 1$ $color(white)(xxx)=color(blue)0-1$
$\times x = - 1$ $color(white)(xxx)=-1$

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What is the solution to the system of equations $x = y - 1$ $x = y - 1$ and $2 x + y = - 2$ $2x + y = -2$ ?

1 Answer

Explanation:

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