What is the distance between (8, 2) and (4, 7) ?

1 Answer
Dec 29, 2015

Its sqrt(41)

Explanation:

We first need to calculate the difference in x axis and in y axis:
trianglex = 8 - 4 = 4
triangley = 7 - 2 = 5
Having this values, we now have a triangle rectangle with angles in both points. Now, just apply Pythagoras' formula:
"line"^2 = trianglex^2 + triangley^2
"line"^2 = 4^2 + 5^2
"line" = sqrt(41)