Question

What is the distance between `(8, 2)` and # (4, 7) #?

Answer 1

Its `sqrt(41)`

Explanation:

We first need to calculate the difference in x axis and in y axis:
`trianglex = 8 - 4 = 4`
`triangley = 7 - 2 = 5`
Having this values, we now have a triangle rectangle with angles in both points. Now, just apply Pythagoras' formula:
`"line"^2 = trianglex^2 + triangley^2`
`"line"^2 = 4^2 + 5^2`
`"line" = sqrt(41)`