How do you solve the following system: 8x−3y=3,7x−2y=−67?

1 Answer
Anjali_Sharma · Roella W.
Dec 30, 2015

We can use any of the 3 methods to solve it: Substitution, Elimination or Cross multiplication method.
I am using substitution method here to solve this system.

Explanation:

This is how we do this:
8x−3y=3 (equa.1)
x=3+3y8

7x−2y=−67 (equa.2)
putting the value of 'x' in equation 2
7⋅3+3y8−2y=−67
21+21y8−2y=−67
21+21y−16y=−67⋅8
21+5y=−536
5y=557
y=5575
now put the value of y in the equation 1 for getting the value of x.

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