What is the standard form of y=(6x−4)(x+3)−(2x−1)(3x−2)?

1 Answer
Júlio B. · Tanish J.
Dec 30, 2015

21x−y=14

Explanation:

To find the standard form, you have to multiply the content of the parenthesis. First, the first pair:
The first number of the first parenthesis multiplies the numbers in the second one: 6x⋅x+6x⋅3=6x2+18x. Then we add the multiplication of the second number in the first parenthesis by the numbers in the second one: −4⋅x+(−4)⋅3=−4x−12 and join them
:
6x2+18x−4x−12=6x2+14x−12.

Now, just do the same with the second pair:

2x⋅3x+2x⋅(−2)=6x2−4x and (−1)⋅(3x)+(−1)⋅(−2)=−3x+2

And now put them together: 6x2−4x−3x+2=6x2−7x+2

And, finally, join the content from the two parenthesis:
y=6x2+14x−12−(6x2−7x+2)=
y=6x2−6x2+14x+7x−12−2=
y=21x−14

The standard form of a linear equation is Ax+By=C

Therefore, we can re-arrange the terms to bring the equation in its standard form as:

21x−y=14

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