What is the standard form of y=(6x4)(x+3)(2x1)(3x2)?

1 Answer
Dec 30, 2015

21xy=14

Explanation:

To find the standard form, you have to multiply the content of the parenthesis. First, the first pair:
The first number of the first parenthesis multiplies the numbers in the second one: 6xx+6x3=6x2+18x. Then we add the multiplication of the second number in the first parenthesis by the numbers in the second one: 4x+(4)3=4x12 and join them
:
6x2+18x4x12=6x2+14x12.

Now, just do the same with the second pair:

2x3x+2x(2)=6x24x and (1)(3x)+(1)(2)=3x+2

And now put them together: 6x24x3x+2=6x27x+2

And, finally, join the content from the two parenthesis:
y=6x2+14x12(6x27x+2)=
y=6x26x2+14x+7x122=
y=21x14

The standard form of a linear equation is Ax+By=C

Therefore, we can re-arrange the terms to bring the equation in its standard form as:

21xy=14