What does $arcsin (cos (\frac{- π}{6}))$ $arcsin(cos ((-pi)/6))$ equal?

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What does $arcsin (cos (\frac{- π}{6}))$ $arcsin(cos ((-pi)/6))$ equal?

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Answer 1 · 2016-01-01T11:03:56

$\frac{π}{3}$ $pi/3$

Explanation:

$cos (- \frac{π}{6}) = cos (\frac{π}{6}) = \frac{\sqrt{3}}{2}$ $cos(-pi/6) = cos(pi/6) = sqrt(3)/2$

$arcsin (\frac{\sqrt{3}}{2}) = \frac{π}{3}$ $arcsin(sqrt(3)/2)=pi/3$ Note range of $arcsin (x)$ $arcsin(x)$ is $[- \frac{π}{2}, \frac{π}{2}]$ $[-pi/2,pi/2]$

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What does $arcsin (cos (\frac{- π}{6}))$ $arcsin(cos ((-pi)/6))$ equal?

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What does $arcsin (cos (\frac{- π}{6}))$ $arcsin(cos ((-pi)/6))$ equal?