Question

How do I find the derivative of `y=ln((x^2)+1)`?

Answer 1

It's going to demand chain rule, which states that `(dy)/(dx)=(dy)/(du)(du)/(dx)`

Explanation:

Renaming `u=x^2+1`, we get `y=ln(u)` and now all we need is to apply the rule.

`(dy)/(dx)=1/u(2x)=(2x)/(x^2+1)`