How do you evaluate the integral of #int (2-x)/(1- x^2)#?
1 Answer
Jan 2, 2016
Explanation:
Use partial fraction decomposition to rewrite the integrant before evaluate the integral
As partial fraction
#A(1+x) + B(1-x) = 2-x#
When you solve the system
Rewrite the integral as
# -1/2 ln|1-x| + 3/2 ln|1+x| +C# or
#1/2 (3 ln|1+x| -ln|1-x|)+ C#