How do you solve the following system: #5x+2y=12, 4x-y=6 #?

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Answer 1 · 2016-01-02T07:18:22

#x=24/23, y=18/13#

By substitution

#5x+2y=12# ---#(1)#

#4x-y=6#

#y=4x-6# ---#(2)#

Substitute equation #(2)# into equation #(1)#

#5x+2(4x-6)=12#

#5x+8x-12=12#

#13x=24#

#x=24/13#

Substitute #x=24/13# into equation #(2)#

#y=4(24/13)-6#

#y=96/13-6#

#y=18/13#

thus, #x=24/23, y=18/13#