How do you simplify $(- 1 - 8 i) + (4 + 3 i)$ $(-1-8i)+(4+3i)$ and write in a+bi form?

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Answer 1 · 2016-01-02T22:49:30

$(- 1 - 8 i) + (4 + 3 i) = 3 - 5 i$ $(-1-8i)+(4+3i)=3-5i$

When adding complex numbers given in a+bi form, we add real parts and imaginary parts separately:

$(- 1 - 8 i) + (4 + 3 i) = - 1 + 4 - 8 i + 3 i =$ $(-1-8i)+(4+3i)=-1+4-8i+3i=$
$= (- 1 + 4) + (- 8 + 3) i = 3 - 5 i$ $=(-1+4)+(-8+3)i=3-5i$

We could think about complex numbers as vectors on the complex plane, where real part is on x axis and imaginary part is on y axis.

How do you simplify (−1−8i)+(4+3i)(-1-8i)+(4+3i) and write in a+bi form?