What is the standard form of $y = (\frac{3}{5} x^{2} - \frac{1}{2}) (\frac{1}{6} x + \frac{7}{8})$ $y= (3/5x^2-1/2)(1/6x+7/8)$ ?

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Answer 1 · 2016-01-03T17:18:11

$y = \frac{1}{10} x^{3} + \frac{21}{40} x^{2} - \frac{1}{12} x - \frac{7}{16}$ $y=1/10x^3+21/40x^2-1/12x-7/16$

Distribute using the FOIL method.

$y=overbrace(3/5x^2(1/6x))^("first")+overbrace(3/5x^2(7/8))^("outside")+overbrace(-1/2(1/6x))^("inside")+overbrace(-1/2(7/8))^("last")$

Multiply the fractions.

$y=1/10x^3+21/40x^2-1/12x-7/16$

This is in standard form since the degree of the each term is lower than the previous .

What is the standard form of y= (3/5x^2-1/2)(1/6x+7/8) y=(35x2−12)(16x+78)y= (3/5x^2-1/2)(1/6x+7/8) ?