If a projectile is shot at a velocity of #2 m/s# and an angle of #pi/4#, how far will the projectile travel before landing?
1 Answer
it will land about 0.638 m far.
Explanation:
We have to write down the equations of motion:
where
We have:
#h_0=0# and#x_0=0# ;#v=2 \ ms^(-1)# #theta= pi/4 # #a=-g \ ~~ -9.81 \ ms^(-2). #
We have
When the projectile lands, it reaches the ground so we have y=0 at that moment.
The equations of motion at the landing are:
from the first equation
The other becomes:
Performing the calculation we eventually have: