Question

What is the distance between `(8,0,6)` and `(1,-4,5)`?

Answer 1

`d = sqrt(66)`

Explanation:

Distance in 3D is just pythagoras, except you now have a term for the z coordinates.

`d^2 = (8-1)^2 + (0+4)^2 + (6-5)^2`
`d^2 = (7)^2 + (4)^2 + (1)^2`
`d^2 = 49 + 16 + 1`
`d^2 = 66`
`d = sqrt(66)`