What is the second derivative of f(x) = x^2ln x ?

1 Answer
Jan 7, 2016

3+ 2lnx

Explanation:

Let's get the first derivative f'(x) first by applying the product rule:
f(x) = x^2lnx
f'(x) = x^2(1/x) + (lnx)(2x)
f'(x) = x + 2xlnx

Get the second derivative f''(x) by differentiating the first derivative:
Differentiate term by term. Apply product rule on the second term
f'(x) = x + 2xlnx
f''(x) = 1 + 2x(1/x) + (lnx)(2)
f''(x) = 1 + 2 + 2lnx
f''(x) = 3+ 2lnx