Question

How do you solve `tan 27 = cot (x+9)`?

Answer 1

`x=54^o`

Explanation:

One approach which makes sense is using the identity

`tan(90-theta)=cot(theta)`

`tan(27) = cot(x+9)`
`tan(90-63)=cot(x+9)`
`cot(63) = cot(x+9)`
`63 = x+ 9`
subtract `9` from both the sides.

`63-9=x+9-9`
`54 = x`

`x=54^o` is the answer.