How do you find all the real and complex roots of #z^5 =1#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Tom Jan 9, 2016 Real : #z_0 = 1# Complex : #z_1 = -e^((pii)/5)# #z_2 = e^((2pii)/5)# #z_3 = -e^((3pii)/5)# #z_4 = e^((4pii)/5)# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1365 views around the world You can reuse this answer Creative Commons License