For what values of x, if any, does f(x) = 1/((x+8)(x-2)) f(x)=1(x+8)(x−2) have vertical asymptotes?
1 Answer
Jan 10, 2016
Vertical asymptotes at x = -8 and and x = 2
Explanation:
A graph will have vertical asymptotes when you would divide by zero. This will occur when the denominator is zero - i.e. when either of the brackets equals zero.
Solve x+8 =0 and x-2=0 for your asymptotes.
