How do you solve the rational equation $(y+2)/y = 1/(y-5)$ ?

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Answer 1 · 2016-01-10T11:37:12

$y=2+-sqrt(14)$

Multiply through by the denominators to remove the fractions.

$(y+2)(y-5)=y$

Expand and solve.

$y^2-3y-10=y$
$y^2-4y-10=0$
$(y-2)^2-14=0$
$y=2+-sqrt(14)$

How do you solve the rational equation (y+2)/y = 1/(y-5)(y+2)/y = 1/(y-5)?