What is the force, in terms of Coulomb's constant, between two electrical charges of $24 C$ $24 C$ and $32 C$ $32 C$ that are $12 m$ $12 m$ apart?

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Answer 1 · 2016-01-10T16:30:45

If $q_{1}$ $q_1$ and $q_{2}$ $q_2$ are charges and $r$ $r$ is the distance between them then the force $F$ $F$ between them is given by

$F = \frac{k q_{1} q_{2}}{r^{2}}$ $F=(kq_1q_2)/r^2$

Where $k$ $k$ is a constant and is known as Coulomb's force constant

Here Let $q_{1} = 24 C$ $q_1=24C$ , $q_{2} = 32 C$ $q_2=32C$ and $r = 12 m$ $r=12m$ ,

$F = \frac{k \cdot 24 \cdot 32}{12^{2}}$ $F=(k*24*32)/12^2$

$\Rightarrow F = \frac{768 k}{144} =$ $implies F=(768k)/144=$

$\Rightarrow F = 5.33 k N$ $implies F=5.33kN$

Since the force is positive so the force between the charges is repullsive

What is the force, in terms of Coulomb's constant, between two electrical charges of 24C24 C and 32C32 C that are 12m12 m apart?