How do you solve $(3x-4) / 6 + 1/3 =( 3x) / 2$ ?

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Answer 1 · 2016-01-11T00:47:26

$x=-1/3$

$(3x-4)/6+1/3-(3x)/2=0$

$LCD =6$ (Lowest Common Denominator)

$(1*(3x-4)+2*1-3*3x)/6=0$

$3x-4+2-9x=0$

$-6x-2=0$

$-6x=2$

$6x=-2$

$x=-cancel(2)^1/cancel(6)^3=-1/3$

How do you solve (3x-4) / 6 + 1/3 =( 3x) / 2(3x-4) / 6 + 1/3 =( 3x) / 2?