How do you factor the expression #49y^2 + 112y + 64#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Lucio Falabella Jan 11, 2016 #49y^2+112y+64=(7y+8)^2# Explanation: #49y^2+112y+64=7^2y^2+2*7*8y+8^2=# #=(7y)^2+2*7*8y+8^2# Use the Square of a binomial rule #(a+b)^2=(a^2+2ab+b^2)# with: #a=7y# #b=8# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1629 views around the world You can reuse this answer Creative Commons License