How do you solve the inequality #162 > -3a(5+1)#?

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Answer 1 · 2016-01-11T16:55:32

#a> -9#

#162>(-3a(5+1))#

#:.162>(-3a*6)#

#:.cancel(162)^27/cancel(6)^1>(-3a*cancel(6)^1/cancel(6)^1)#

#:.27>(-3a)#

We can change sign and string inequality operator

#:.color(red)-27color(red)<3a#

We can change sign and

#:.3a> -27#

#a> -cancel(27)^9/cancel(3)^1#

#a> -9#