How do you rewrite $y = 4 {(3)}^{2 x + 2}$ $y = 4(3)^(2x+2)$ in $y = a \cdot b^{x}$ $y = a * b^x$ form?

Question

How do you rewrite $y = 4 {(3)}^{2 x + 2}$ $y = 4(3)^(2x+2)$ in $y = a \cdot b^{x}$ $y = a * b^x$ form?

2 Answers

Impact of this question

1614 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-12T12:34:12

$y = 4 \cdot 3^{2 x + 2} = 36 \cdot 9^{x}$ $y=4*3^(2x+2)=36*9^x$

with:

$a = 36$ $a=36$
$b = 9$ $b=9$

Explanation:

Remembering that:

$a^{p + q} = a^{p} \cdot a^{q}$ $a^(p+q)=a^p*a^q$

${(a^{n})}^{m} = a^{n \cdot m}$ $(a^n)^m=a^(n*m)$

then:

$y = 4 \cdot 3^{2 x + 2} = 4 \cdot 3^{2 x} \cdot 3^{2} =$ $y=4*3^(2x+2)=4*3^(2x)*3^2=$
$= 4 \cdot 9 \cdot {(3^{2})}^{x} = 36 \cdot 9^{x}$ $=4*9*(3^2)^x=36*9^x$

Answer 2 · 2016-01-12T12:38:15

$y = 4 {(3)}^{2 x + 2} \Leftrightarrow y = 36 \cdot 9^{x}$ $y=4(3)^(2x+2)hArr y=36*9^x$

Explanation:

$4 {(3)}^{2 x + 2}$ $4(3)^(2x+2)$

$XXX = 4 \cdot ({(3^{2})}^{x + 1})$ $color(white)("XXX")=4*((3^2)^(x+1))$

$XXX = 4 \cdot (9^{x + 1})$ $color(white)("XXX")=4*(9^(x+1))$

$XXX = 4 \cdot (9 \cdot 9^{x})$ $color(white)("XXX")=4*(9*9^x)$

$XXX = 4 \cdot 9 \cdot (9^{x})$ $color(white)("XXX")=4*9*(9^x)$

$XXX = 36 \cdot 9^{x}$ $color(white)("XXX")=36*9^x$

Science

Math

Humanities

... and beyond

How do you rewrite $y = 4 {(3)}^{2 x + 2}$ $y = 4(3)^(2x+2)$ in $y = a \cdot b^{x}$ $y = a * b^x$ form?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you rewrite y=4(3)2x+2y = 4(3)^(2x+2) in y=a⋅bxy = a * b^x form?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you rewrite $y = 4 {(3)}^{2 x + 2}$ $y = 4(3)^(2x+2)$ in $y = a \cdot b^{x}$ $y = a * b^x$ form?