Question

How do you graph `y-5x=-2` using a table of values?

Answer 1

You would first put it into Slope Intercept Form, then make a chart for values and graph them.
graph{5x-2 [-10, 10, -5, 5]}

Explanation:

First, I'm going to put your equation in slope Intercept form. This follows the following form: `Y=MX+B`. Essentially, I only want the Y value to be on the left side of the = sign. That's slope intercept form. This step isn't necessary but it makes things easier.

To do this, I'm going to add `-5x` to both sides to get `Y = 5X -2`.

Now, you need to make a table of values for X and Y values. It helps to put in a bunch of X values first. Maybe start by inserting numbers between -3 and 3. Here's the chart so far.
X | Y
-3
-2
-1
0
1
2
3

Next, you want to take each X value and fill it in for the X in the equation. Write whatever you get for the solution of each equation in for the Y column. Let's start with X=-3.
`Y=5X-2`
`Y=5(-3)-2`
`Y=-15-2`
`Y=-17`
So now we know that if `X=-3`, then `Y=-17`.

I'll do another equation if X=-2
`Y=5X-2`
`Y=5(-2)-2`
`Y=-10-2`
`Y=-12`
If `X=-2` then `Y=-12`.

Once you do every equation, you should get a chart like this:
X | Y
-3, -17
-2, -12
-1, -7
0, -2
1, 3
2, 8
3, 13

Finally, plot each of those points (-3,-17), (-2,-12), etc on a graph. And there we go!