How do you factor the trinomial $r^{2} + 6 r + 5$ $r^2 + 6r + 5$ ?

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How do you factor the trinomial $r^{2} + 6 r + 5$ $r^2 + 6r + 5$ ?

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Answer 1 · 2016-01-20T02:42:23

$(r + 1) (r + 5)$ $(r+1) (r+5)$

Explanation:

This is a quadratic equation. The square root of $r^{2}$ $r^2$ is r. However, the square root of 5 is not a whole number. So, to factor this we have to consider the FOIL method; First term, outer term, inner term and last term.

Remember that, $(a x + b) (a x + c) = ({(a x)}^{2} + b a x + c a x + b c)$ $(ax+b)(ax+c) = ((ax)^2 + bax + cax + bc)$

$(r^{2} + 6 r + 5) = (r + 1) (r + 5)$ $(r^2+ 6r +5) = (r+1) (r+5)$
$(r^{2} + 6 r + 5) = (r^{2} + 1 r + 5 r + 5)$ $(r^2+ 6r +5) = (r^2 + 1r +5r +5)$
$(r^{2} + 6 r + 5) = (r^{2} + 6 r + 5)$ $(r^2+ 6r +5) = (r^2 + 6r +5)$

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How do you factor the trinomial $r^{2} + 6 r + 5$ $r^2 + 6r + 5$ ?

1 Answer

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Science

Math

Humanities

... and beyond

How do you factor the trinomial r2+6r+5r^2 + 6r + 5?

1 Answer

Explanation:

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Impact of this question

How do you factor the trinomial $r^{2} + 6 r + 5$ $r^2 + 6r + 5$ ?