What is the domain and range of y =1/sqrt(17x+8)y=1√17x+8?
1 Answer
Jan 20, 2016
Domain:
Range:
Explanation:
- Domain
The existence conditions are:
- Range
we have to evaluate:
-
lim_(x rarr (-8/17)^+) f(x)=1/0^+=+oo -
lim_(x rarr (+oo)) f(x)=1/(+oo)=0^+ then #y=0# is a horizontal asymptote for #x rarr +oo#