Question #72d69

Question

803 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-21T00:49:54

#{ (x=2),(y=0):}#

therefore:

#{ (y=x-2),(2x+2y=4):} <=>{ (y=x-2),(cancel(2)x+cancel(2)y=cancel(4)^2):}#

#{ (y=x-2 " s1"),(x+y=2 " s2") :}#

you have already found #y# in #s1# then substitute it in #s2#

#{ (y=x-2),(x+(x-2)=2) :}<=>{ (y=x-2),(2x-2=2) :}#

#<=>{ (y=x-2" s1"),(x=2" s2") :}#

In #s2# you found the #x# value then substitute it in #s1#

#{ (y=2-2),(x=2):}<=>{ (y=0),(x=2):}#