What is $\sqrt{- 16}$ $sqrt(-16)$ , written in the form $a + b i$ $a+bi$ ?

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Answer 1 · 2016-01-21T19:42:27

$0 + 4 i$ $0+4i$

$\sqrt{- 16}$ $sqrt(-16$
$= \sqrt{(- 1) (16)} = \sqrt{- 1} \sqrt{16} = i 4 = 0 + 4 i$ $=sqrt((-1)(16))=sqrt(-1)sqrt(16)=i4=0+4i$

$\Rightarrow \sqrt{- 16} = 0 + 4 i$ $implies sqrt(-16)=0+4i$

What is √−16sqrt(-16), written in the form a+bia+bi?