How do you rewrite #y + 5 = 3(x-9)# in standard form?

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Answer 1 · 2016-01-23T14:37:02

#y - 3x+32=0#

#y + 5 = 3(x-9)#

first, multiple the 3 with the bracket

#y + 5 = 3(x)-3(9)#

then, this what you will get

#y + 5 = 3x-27#

move the right side to left side,

#y + 5 - 3x+27=0#

solve the 5 and 27, and finally u will get the answer

#y - 3x+32=0#