Question

A circuit with a resistance of `8 Omega` has a fuse with a capacity of `5 A`. Can a voltage of `42 V` be applied to the circuit without blowing the fuse?

Answer 1

`No`

Explanation:

Data:-

Resistance`=R=8Omega`

Voltage`=V=42V`

The fuse has capacity of 5A

Sol:-

If we apply voltage `V` across a resistor whose resistance is `R` then the current `I` flowing across it can be calculated by

`I=V/R`

Here we are applying voltage of `42V` across a `8Omega` resistor, therefore, the current flowing is

`I=42/8=5.25` `implies I=5.25A`

Since, the fuse has capacity of `5A` but the current flowing in the circuit is `5.25A` therefore, the fuse will melt. Thus, the answer to this question is `No`.