What is the standard form of #y=5(x-3)^2-7#?

1 Answer
radee
Jan 27, 2016

#y = 5x^2 - 30x + 38#

Explanation:

Since this is a quadratic equation, the standard form should appear this way

#y = ax^2 + bx + c#

In this case, you will have to expand and simplify (if possible) the equation to get the standard form.

[Solution]
#y = 5(x - 3)^2 - 7#
#y = 5(x^2 - 6x + 9) - 7#
#y = 5x^2 - 30x + 45 - 7#
#y = 5x^2 - 30x + 38#

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