Question #bda95

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Question #bda95

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Answer 1 · 2016-01-27T13:48:14

Kinetic energy is calculated using $E_{k} = \frac{1}{2} m v^{2}$ $E_k=1/2mv^2$

Explanation:

If m is mass in kg, and v is speed in m/s, then
$E_{k 1} = \frac{1}{2} \cdot 50 \cdot 5^{2}$ $E_(k1)=1/2*50*5^2$
$E_{k 1} = 25 \cdot 25$ $E_(k1)=25*25$
$E_{k 1} = 625 J$ $E_(k1)=625J$

$E_{k 2} = \frac{1}{2} \cdot 50 \cdot 10^{2}$ $E_(k2)=1/2*50*10^2$
$E_{k 2} = 25 \cdot 100$ $E_(k2)=25*100$
$E_{k 2} = 2500 J$ $E_(k2)=2500J$

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