How do you solve #-5(2x-9)=2(x-8)-11#?

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Answer 1 · 2016-01-27T21:32:40

#x=6#

Semplify the expression following PEMDAS rules:

#-5*2x+5*9=2*x-2*8-11#

#-10x+45=2x-16-11#

Now move all the therms in #x# on the #LHS# and all the costant on the #RHS#, changing the sign when you moving it:

#-10xcolor(red)-2x=color(red)-45-27#

#-12x=-72#

#12x=72#

#x=72/12=>x=6#