How do you solve tan^2 x=tan xtan2x=tanx?

1 Answer
Jan 28, 2016

x = kpix=kπ or x = pi/4 + kpix=π4+kπ where k in ZZ

Explanation:

tan^2x = tanx

=> tan^2x - tanx = 0

=> tanx(tanx - 1) = 0

=> tanx = 0 or tanx = 1

=> sinx/cosx = 0 or sinx/cosx = 1

=> sinx = 0 or sinx = cosx

:. x = kpi or x = pi/4 + kpi where k in ZZ