What is the equation of the line perpendicular to $y=-7/15$ that passes through $(-25,5)$ ?

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Answer 1 · 2016-01-29T14:32:08

$x+25=0$

the given line is,
$y=-7/15$

$or,y+7/15=0$

so, the equation of the perpendicular line should be,

$-x+c=0$

now, passing the line throught (-25,5) we get,
$-(-25)+c=0$

$or,25+c=0$

$or,c=-25$

so, the equation is,
$-x-25=0$

$or,x+25=0$

What is the equation of the line perpendicular to y=-7/15 y=-7/15 that passes through (-25,5) (-25,5) ?