What is the equation of the line perpendicular to #y=-7/15 # that passes through # (-25,5) #?

Question

1468 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-29T14:32:08

#x+25=0#

the given line is,
#y=-7/15#

#or,y+7/15=0#

so, the equation of the perpendicular line should be,

#-x+c=0#

now, passing the line throught (-25,5) we get,
#-(-25)+c=0#

#or,25+c=0#

#or,c=-25#

so, the equation is,
#-x-25=0#

#or,x+25=0#