How do you factor the expression #25x^2 - 4#?
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"Suppose that I don't have a formula for #g(x)# but I know that #g(1)
= 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Jan 31, 2016
Both are correct answers :)
Explanation:
Since
(Factoring Difference of Two Squares)
We can do this by "Trial and Error Method".
giving
or
