An object with a mass of $8 k g$ $8 kg$ is traveling in a circular path of a radius of $12 m$ $12 m$ . If the object's angular velocity changes from $15 H z$ $15 Hz$ to $7 H z$ $7 Hz$ in $6 s$ $6 s$ , what torque was applied to the object?

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An object with a mass of $8 k g$ $8 kg$ is traveling in a circular path of a radius of $12 m$ $12 m$ . If the object's angular velocity changes from $15 H z$ $15 Hz$ to $7 H z$ $7 Hz$ in $6 s$ $6 s$ , what torque was applied to the object?

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Answer 1 · 2016-01-31T21:24:07

Torque=-803.52 Newton.meter

Explanation:

$f_{1} = 15 H z$ $f_1=15 Hz$
$f_{2} = 7 H z$ $f_2=7 Hz$
$w_{1} = 2 \cdot 3.14 \cdot 15 = 30 \cdot 3.14 = 94.2 \frac{r a d}{s}$ $w_1=2*3.14*15 =30*3.14=94.2( rad)/s$
$w_{2} = 2 \cdot 3.14 \cdot 7 = 14 \cdot 3.13 = 43.96 \frac{r a d}{s}$ $w_2=2*3.14*7=14*3.13=43.96 (rad)/s$
$a = \frac{w_{2} - w_{1}}{t}$ $a=(w_2-w_1)/t$
$a = \frac{43.96 - 94.2}{6}$ $a=(43.96-94.2)/6$
$a = - 8.37 \frac{m}{s^{2}}$ $a=-8.37 m/s^2$
$F = m \cdot a$ $F=m*a$
$F = - 8 \cdot 8.37 = - 66.96 N$ $F=-8*8.37=-66.96 N$
$M = F \cdot r$ $M=F*r$
$M = - 66.96 \cdot 12 = - 803.52$ $M=-66.96*12=-803.52$ , Newton.meter

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An object with a mass of $8 k g$ $8 kg$ is traveling in a circular path of a radius of $12 m$ $12 m$ . If the object's angular velocity changes from $15 H z$ $15 Hz$ to $7 H z$ $7 Hz$ in $6 s$ $6 s$ , what torque was applied to the object?

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Explanation:

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An object with a mass of 8kg 8 kg is traveling in a circular path of a radius of 12m12 m. If the object's angular velocity changes from 15Hz 15 Hz to 7Hz 7 Hz in 6s 6 s, what torque was applied to the object?

1 Answer

Explanation:

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An object with a mass of $8 k g$ $8 kg$ is traveling in a circular path of a radius of $12 m$ $12 m$ . If the object's angular velocity changes from $15 H z$ $15 Hz$ to $7 H z$ $7 Hz$ in $6 s$ $6 s$ , what torque was applied to the object?