How do you evaluate $sin (11 \frac{π}{2})$ $sin(11(pi)/2)$ ?

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How do you evaluate $sin (11 \frac{π}{2})$ $sin(11(pi)/2)$ ?

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Answer 1 · 2016-02-01T09:04:34

Explanation is given below

Explanation:

$sin (\frac{11 π}{2})$ $sin((11pi)/2)$
$= sin (6 π - \frac{π}{2})$ $=sin(6pi-pi/2)$

Note $sin (2 n π - θ) = - sin (θ)$ $color(magenta)(sin(2npi - theta) = -sin(theta)$
and $sin (2 n π + θ) = sin (θ)$ $color(magenta)(sin(2npi + theta) = sin(theta)$

$= - sin (\frac{π}{2})$ $=-sin(pi/2)$
$= - 1$ $=-1$

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How do you evaluate $sin (11 \frac{π}{2})$ $sin(11(pi)/2)$ ?

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