How do you simplify $(8 - 3 i) + (- 6 + 2 i)$ $(8 - 3i) + (-6 + 2i)$ ?

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Answer 1 · 2016-02-01T16:49:37

$(8 - 3 i) + (- 6 + 2 i) = 2 - i$ $(8-3i)+(-6+2i)=2-i$

Remove the parenthesis and convert like terms.

$(8 - 3 i) + (- 6 + 2 i)$ $(8-3i) + (-6+2i)$

$= 8 - 3 i - 6 + 2 i$ $=8-3i-6+2i$

$= 8 - 6 - 3 i + 2 i$ $=8-6-3i+2i$

$= 2 - i$ $=2-i$

How do you simplify (8−3i)+(−6+2i)(8 - 3i) + (-6 + 2i)?