Question

How do you simplify `sqrt3^2`?

Answer 1

Ambiguous

Explanation:

I cannot understand if the square is inside or outside the radix. Anyhow, if it's inside (the most plausible one...)
`sqrt(3^2)` it's one of the two numbers `+-a` such that `(+-a)^2=3^2=9`, so they are `sqrt(3^2)= +-3`
On the other hand, if we consider `(sqrt(3))^2`, you gotta take both `+-sqrt(3)` and take the square. But, by definition, `+-sqrt(3)` are the only two numbers such that `(+-sqrt(3))^2=3`, so the answer is `3`

Answer 2

Ambiguous

Explanation:

I cannot understand if the square is inside or outside the radix. Anyhow, if it's inside (the most plausible one...)
`sqrt(3^2)` it's one of the two numbers `+-a` such that `(+-a)^2=3^2=9`, so they are `sqrt(3^2)= +-3`
On the other hand, if we consider `(sqrt(3))^2`, you gotta take both `+-sqrt(3)` and take the square. But, by definition, `+-sqrt(3)` are the only two numbers such that `(+-sqrt(3))^2=3`, so the answer is `3`