What is the norm of #< 5 , -2, 3 >#? Physics 2D Motion Vector Operations 1 Answer Iván Á. Feb 3, 2016 #\sqrt 38# Explanation: Just using pithagoras theorem you know #h=\sqrt(x_1^2+x_2^2+x_3^2+x_4^2+...)# as you are in three dimensional vectorial space, you stop at the third component. so #|V|=\sqrt(5^2+(-2)^2+3^2)=\sqrt(38)# Answer link Related questions What are vectors used for? Why vectors cannot be added algebraically? How do we represent the magnitude of a vector in physics? How do you find the equation of a vector orthogonal to a plane? Why are vectors important? How does a vector quantity differ from a scalar quantity? How can I calculate the magnitude of vectors? How do vectors subtract graphically? How do force vectors affect an object in motion? How can vectors be represented? See all questions in Vector Operations Impact of this question 1369 views around the world You can reuse this answer Creative Commons License