How much power is required to lift an object of weight $595$ $595$ newtons by $3.15$ $3.15$ meters in $15.2$ $15.2$ seconds?

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How much power is required to lift an object of weight $595$ $595$ newtons by $3.15$ $3.15$ meters in $15.2$ $15.2$ seconds?

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Answer 1 · 2016-02-10T13:59:46

Power output is $123.306$ $123.306$ watts.

Explanation:

Potential Energy (in Joules) $P E$ $PE$ gained is given by

$P E$ $PE$ = $m \cdot g \cdot h$ $m*g*h$ , where $m$ $m$ is mass in kilograms, $g$ $g$ is acceleration due to gravity ( $9.8$ $9.8$ meters per $sec o n d^{2}$ $second^2$ ) and $h$ $h$ is height in meters. We can also write this as $P E$ $PE$ = $w \cdot h$ $w*h$ , where $w$ $w$ is weight in Newtons - as it is given in Newtons here. (Obviously $w = m \cdot g$ $w=m*g$ ).

Power in watts is given by $\frac{P E}{t}$ $(PE)/t$ , where $t$ $t$ is times in seconds.

Accordingly $P E$ $PE$ here is $595 \cdot 3.15$ $595*3.15$ or $1, 874.25$ $1,874.25$ and

Power output is $\frac{1874.25}{15.2}$ $1874.25/15.2$ or $123.306$ $123.306$ watts.

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How much power is required to lift an object of weight $595$ $595$ newtons by $3.15$ $3.15$ meters in $15.2$ $15.2$ seconds?

1 Answer

Explanation:

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