An object with a mass of 3 kg3kg is traveling in a circular path of a radius of 15 m15m. If the object's angular velocity changes from 5 Hz5Hz to 3Hz3Hz in 5 s5s, what torque was applied to the object?

1 Answer
Feb 10, 2016

L=-540piL=540π

Explanation:

alpha=L/Iα=LI
alpha": angular acceleration"α: angular acceleration
"L:torque"L:torque
"I:moment of inertia"I:moment of inertia
alpha=(omega_2-omega_1)/ (Delta t)
alpha=(2 pi*3-2 pi*5)/5
alpha=-(4pi)/5
I=m*r^2
I=3*15^2
I=3*225=675
L=alpha*I
L=-4pi/5*675
L=-540pi