What torque would have to be applied to a rod with a length of #1 m# and a mass of #2 kg# to change its horizontal spin by a frequency of #6 Hz# over #4 s#?
1 Answer
The angular acceleration is
Explanation:
First find the angular acceleration,
The angular velocity is 6 Hz, and 1 Hz means that a circle of 2
Torque = moment of inertia *
moment of inertia depends on the shape of the spinning object and can be complicated. Fortunately for a mass on a rod it's simple:
moment of inertia = mass *
so:
moment of inertia = 2kg *
Now we have:
Torque = (2 kg
Torque = 6
or approximately :
Torque