An object with a mass of $4 k g$ $4 kg$ is hanging from a spring with a constant of $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ . If the spring is stretched by $8 m$ $8 m$ , what is the net force on the object?

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An object with a mass of $4 k g$ $4 kg$ is hanging from a spring with a constant of $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ . If the spring is stretched by $8 m$ $8 m$ , what is the net force on the object?

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Answer 1 · 2016-02-11T18:05:53

$F_{n} = - 24, 76 N$ $F_n=-24,76 N$

Explanation:

$G = m \cdot g = 4 \cdot 9, 81 = 39, 24 N this is object's weight$ $G=m*g=4*9,81=39,24 N "this is object's weight "$
$F=-k*Delta x$
$F=-8*8=-64 N "stretched force on spring"$
$F_n=-64+39,24$
$F_n=-24,76 N$

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An object with a mass of $4 k g$ $4 kg$ is hanging from a spring with a constant of $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ . If the spring is stretched by $8 m$ $8 m$ , what is the net force on the object?

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An object with a mass of 4 kg4kg4 kg is hanging from a spring with a constant of 8 (kg)/s^28kgs28 (kg)/s^2. If the spring is stretched by 8 m8m8 m, what is the net force on the object?

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An object with a mass of $4 k g$ $4 kg$ is hanging from a spring with a constant of $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ . If the spring is stretched by $8 m$ $8 m$ , what is the net force on the object?