Question #716c5

1 Answer
Feb 12, 2016

The frictional force experienced by block is #0.98N#

Explanation:

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Here's how your question looks like diagrammatically.

Given force #F# of #5N# is applied to the box to keep it on the surface.
The box is of #0.1kg# and its subsequent weight is #0.98N#
Since the normal force is the equal to the force exerted on the surface by the box, then #N=F=5N#
That means the maximum static frictional force the surface can exert is #\mu_sN=0.5*5=2.5N#

But this isn't the end of it yet. We have to find out what exactly the frictional force is. Because even if the maximum frictional force is #2.5N#, this isn't the force always experienced, it actually also depends on the force that causes the box to move, which here would be the force of gravity #Mg#
Seeing that #Mg=0.98N#, this means that the force of friction experienced by the object is actually #0.98N#
This is because the only maximum force of friction depends on normal force, but the value the object will experience will be the force that tries to move it.