There is a population of 5 bacteria in a colony. If the number of bacteria doubles every 115 minutes, what will the population be 345 minutes from now?

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Answer 1 · 2016-02-13T01:57:21

This is an exponential growth problem: $A_{0} r^{t}$ $A_0r^t$

For this problem the initial population $A_{0} = 5$ $A_0=5$

The rate of growth $r = 2$ $r=2$

The time factor is based on a duration of 115 minutes:

$t = \frac{345}{115} = 3$ $t=345/115=3$ durations

Insert the values into the growth equation:

$A_{0} r^{t}$ $A_0r^t$

$5 {(2)}^{3} = 5 \times 8 = 40$ $5(2)^3=5xx8=40$ bacteria 345 minutes from now

Hope that helped