If a projectile is shot at a velocity of $52 \frac{m}{s}$ $52 m/s$ and an angle of $\frac{π}{3}$ $pi/3$ , how far will the projectile travel before landing?

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If a projectile is shot at a velocity of $52 \frac{m}{s}$ $52 m/s$ and an angle of $\frac{π}{3}$ $pi/3$ , how far will the projectile travel before landing?

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Answer 1 · 2016-02-13T13:36:57

$x_(max)~=103,358m$

Explanation:

$"you can calculate by: "x_(max)=(v_i^2*sin^2 alpha)/(2*g)$
$v_i:"initial velocity"$
$alpha:" projectile angle"$
$g:"gravitational acceleration"$
$alpha=pi/3*180/pi=60^o$
$sin 60^o=0,866$
$sin^2 60^o=0,749956$
$x_(max)=(52^2*0,749956)/(2*9,81)$
$x_(max)~=103,358m$

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If a projectile is shot at a velocity of $52 \frac{m}{s}$ $52 m/s$ and an angle of $\frac{π}{3}$ $pi/3$ , how far will the projectile travel before landing?

1 Answer

Explanation:

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If a projectile is shot at a velocity of $52 \frac{m}{s}$ $52 m/s$ and an angle of $\frac{π}{3}$ $pi/3$ , how far will the projectile travel before landing?