How do you solve #22 -5(6v-1) = -63#?

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Answer 1 · 2016-02-13T20:32:33

#-1.2#

Follow the rule BODMAS so
1: #22 - 30v + 5= 63#
2:#-30v= 63-27#
3:#-30v=36#
4:#v=36 divide -30#
5:#v= -1.2#

Answer 2 · 2016-02-14T11:08:38

#color(green)(v=3#

#color(blue)(22-5(6v-1)=-63#

Use distributive property #color(orange)(a(b+c)=ab+ac#

#rarr22-30v+5=-63#

#rarr27-30v=-63#

Subtract #27# both sides

#rarr-30v=-63-27#

#rarr-30v=-90#

#rarrcolor(green)(v=(-90)/-30=90/30=9/3=3#